Mark scheme
(a) [2]
- E, L, G, J (2)
- ALLOW 1 mark for an order with one adjacent pair swapped, or for the correct order written least to most reactive
(b) [2]
- J (1)
- J does not react with dilute hydrochloric acid, because copper is below hydrogen in the reactivity series / J is the least reactive metal (1)
(c) [2]
- calcium (1)
- E reacts (steadily) with cold water, whereas magnesium reacts only very slowly with cold water (and reacts quickly only with steam) (1)
- ALLOW calcium reacts readily with cold water, forming (alkaline) calcium hydroxide
(d) [1]
- any one from: concentration of acid / volume of acid / temperature / size or mass or surface area of the metal pieces (1)
Worked solution
(a) Use each experiment in turn.
- Experiment 1: only E reacts with cold water, so E is the most reactive.
- Experiment 2: with acid, L bubbles rapidly, G slowly and J not at all, so L > G > J.
- Experiment 3: L takes the oxygen from G's oxide, so L is more reactive than G. This agrees with Experiment 2.
Overall order: E, L, G, J.
(b) Copper is below hydrogen in the reactivity series, so it does not react with dilute hydrochloric acid. The only metal that gave no bubbles with acid is J. J is also the least reactive of the four, which fits copper.
(c) Calcium reacts steadily with cold water, giving bubbles of hydrogen and an alkaline solution of calcium hydroxide. Magnesium reacts only very slowly with cold water (it needs steam to react quickly), so you would not see steady fizzing. E is therefore calcium.
(d) To compare reactivity fairly, only the metal should change. Keep the concentration and volume of acid, the temperature and the size of the metal pieces the same.